2x-0,2*x^2=80-4x

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Solution for 2x-0,2*x^2=80-4x equation: 



2x-0.2x^2=80-4x

We move all terms to the left:

2x-0.2x^2-(80-4x)=0

We add all the numbers together, and all the variables

-0.2x^2+2x-(-4x+80)=0

We get rid of parentheses

-0.2x^2+2x+4x-80=0

We add all the numbers together, and all the variables

-0.2x^2+6x-80=0

a = -0.2; b = 6; c = -80;
Δ = b2-4ac
Δ = 62-4·(-0.2)·(-80)
Δ = -28
Delta is less than zero, so there is no solution for the equation

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